Preliminaries
Let be a group, assume that is a normal subgroup of , is a subgroup of , , and . Suppose that acts on by automorphisms of , then there exists a homomorphism . Assume the action is by conjugation, then for and we have . is an internal semidirect product of and by , it is denoted by [1].
Non-abelian groups of orders , for a prime are of two types [1]:
Thus,
and
Let be a field. A ring with unity is an algebra over (breifly -algebra) if is a vector space over and the following compatibility condition holds for any and any . is also called associative algebra (over ). The dimension of the algebra is the dimension of as a vector space over .
Theorem 1 [2]
Let be a -dimensional algebra over a field . Then there is a one-to-one algebra homomorphism from into , the algebra of -matrices over .
Let be a finite group of order and a field. Define . is -dimensional vector space over with basis . Multiplication of can be extended linearly to . Thus, becomes an algebra over of dimension . is called group algebra. The following identifications should be realized:
-
for any .
-
for any . In particular .
-
for any .
A circulant matrix on parameters is defined as follows:
This matrix may be denoted in terms of its columns by .
is said to be circulant block matrix if it is of the form i.e., it is circulant blockwise on the blocks .
Thus,
Main Results
Theorem 2 [3]
Let be a field and a cyclic group of order . Then any element of can be represented with respect to the ordered basis by the circulant matrix .
Proof
Let be in . Then the matrix representation of with respect to the basis is which is .
Note that if the order of the basis elements is changed, we obtain a different matrix of representation. The new matrix is obtained by suitable interchanging of the columns of the matrix . In [4] the representation is done for the non-split metacyclic group.
For more complicated finite groups we use the circulant block matrices to do the required representations.
Now, let be an internal semidirect product of and a cyclic group by .
Then the matrix representation of the general element in is given as follows:
, is a homomorphism, . Suppose that , then the general element in is . Now we can write as:
where
The matrix representation of is , where is the automorphism and , . Thus, we get the following theorem:
Theorem 3
With the above notations, the matrix representation of the general element in .
Applications
Finally, we use theorem 3 to compute the matrix representations of and , when the prime .
1)
.
The general element of is . Let , , . Then .
By theorem 3, matrix representation of is
, is a homomorphism such that
, , , , , , , , .
, , , , , , , .
2)
The general element of is .
Then .
The matrix representation of is
, is a homomorphism such that .
, , , , , , , , .
, , , , , , , , .
For greater prime , the same method may be applied.
Conflict of Interest
Conflict of Interest: Authors declare that they do not have any conflict of interest.